40x^3-8x^2-12x/4x

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Solution for 40x^3-8x^2-12x/4x equation: 


x in (-oo:+oo)

40*x^3-(8*x^2)-(((12*x)/4)*x) = 0

40*x^3-8*x^2-3*x^2 = 0

40*x^3-11*x^2 = 0

x^2*(40*x-11) = 0

40*x-11 = 0 // + 11

40*x = 11 // : 40

x = 11/40

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in { 11/40, 0 }

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